Power

AP Physics 1· difficulty 4/5

A 1500 kg car accelerates from 0 to 20 m/s in 5.0 s on level road. The average power output is closest to (ignore air drag)

  • A

    300 kW

  • B

    60 kW (P=ΔKE/ΔtP = \Delta KE / \Delta t)

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  • C

    30 kW

  • D

    60 kW

Explanation

ΔKE=0.5(1500)(202)=300,000\Delta KE = 0.5(1500)(20^2) = 300{,}000 J = 300 kJ. Average power = 300/5 = 60 kW.

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