Kinetic and Static Friction

AP Physics 1· difficulty 1/5

A spring stretches 0.04 m0.04~\text{m} when a 20 N20~\text{N} force is applied. Its spring constant is

  • A

    500 N/m500~\text{N/m}

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  • B

    5 N/m5~\text{N/m}

  • C

    80 N/m80~\text{N/m}

  • D

    0.8 N/m0.8~\text{N/m}

Explanation

F=kxk=F/x=20/0.04=500 N/mF = k x \Rightarrow k = F/x = 20/0.04 = 500~\text{N/m}.

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