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Kinetic and Static Friction

AP Physics 1· difficulty 2/5

A 5.0 kg5.0~\text{kg} block on rough ground (μk=0.20\mu_k = 0.20) is pulled by a horizontal 20 N20~\text{N} force. Using g≈10 m/s2g \approx 10~\text{m/s}^2, its acceleration is

  • A

    0 m/s20~\text{m/s}^2

  • B

    4.0 m/s24.0~\text{m/s}^2

  • C

    5.0 m/s25.0~\text{m/s}^2

  • D

    2.0 m/s22.0~\text{m/s}^2

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Explanation

Friction: fk=μkmg=(0.20)(5)(10)=10 Nf_k = \mu_k m g = (0.20)(5)(10) = 10~\text{N}. Net 20−10=10 N20 - 10 = 10~\text{N}. a=10/5=2.0 m/s2a = 10/5 = 2.0~\text{m/s}^2.

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