school
Acemy

Kinetic and Static Friction

AP Physics 1· difficulty 4/5

Two masses m1=3.0m_1 = 3.0 kg and m2=5.0m_2 = 5.0 kg connected by a cord over a frictionless pulley. The acceleration of the system is closest to (g=10g = 10 m/s²)

  • A

    1.6 m/s²

  • B

    5.0 m/s²

  • C

    10 m/s²

  • D

    2.5 m/s² (a=(m2−m1)g/(m1+m2)a = (m_2 - m_1)g/(m_1 + m_2))

    check_circle

Explanation

a=(5−3)(10)/(3+5)=20/8=2.5a = (5 - 3)(10)/(3 + 5) = 20/8 = 2.5 m/s².

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forwardPredict my AP score

Related questions

auto_awesomeAll Toolsquestion_answerHomework Q&Amenu_bookAP & SAT PreptimelineLearn Mode