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Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 3/5

4 kg 2 kg

A 4.0 kg4.0~\text{kg} block on a frictionless horizontal table is connected by a string over a frictionless pulley to a 2.0 kg2.0~\text{kg} hanging mass. Using g≈10 m/s2g \approx 10~\text{m/s}^2, what is the acceleration of the system?

  • A

    6.7 m/s26.7~\text{m/s}^2

  • B

    2.0 m/s22.0~\text{m/s}^2

  • C

    3.3 m/s23.3~\text{m/s}^2

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  • D

    5.0 m/s25.0~\text{m/s}^2

Explanation

a=mhang gmtable+mhang=(2.0)(10)4.0+2.0≈3.3 m/s2a = \dfrac{m_{\text{hang}}\,g}{m_{\text{table}} + m_{\text{hang}}} = \dfrac{(2.0)(10)}{4.0 + 2.0} \approx 3.3~\text{m/s}^2.

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