For the same Atwood (3.0 and 5.0 kg, a = 2.5 m/s²), the tension in the cord is

37.5 N (T = m1(g + a)) Apply Newton's 2nd law to the lighter mass: T - m1 g = m1 a, so T = m1(g + a) = 3(10 + 2.5) = 37.5 N. Check with m2: m2 g - T = m2 a, so T = m2(g - a) = 5(7.5) = 37.5 N. ✓

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Acemy

Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 4/5

a = 2.5

A
$50 N$
B
$20 N$
C
$T = m_1(g + a)$
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D
$30 N$

Explanation

T - m_1 g = m_1 a

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