Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 2/5

10 N 4 N 3 N

A free-body diagram shows three forces on an object: 10 N10~\text{N} right, 4 N4~\text{N} left, 3 N3~\text{N} up. What is the magnitude of the net force?

  • A

    3 N3~\text{N}

  • B

    7 N7~\text{N}

  • C

    6.7 N6.7~\text{N}

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  • D

    13 N13~\text{N}

Explanation

Net horizontal: 104=6 N10 - 4 = 6~\text{N} right. Net vertical: 3 N3~\text{N} up. Magnitude: 36+9=456.7 N\sqrt{36 + 9} = \sqrt{45} \approx 6.7~\text{N}.

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