Question

Show why the square root addition and subtraction rules are false

Original question: 5 Use positive integer values of m and n to show that these rules are incorrect. a \sqrt{m} + \sqrt{n} = \sqrt{m+n} b \sqrt{m} - \sqrt{n} = \sqrt{m-n}

Expert Verified Solution

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Expert intro: A rule can look believable and still be wrong. With radicals, one clean counterexample is enough to show that a statement is not always true.

Detailed walkthrough

To prove a rule is incorrect, it is enough to find one counterexample.

a) Show that m+n=m+n\sqrt{m} + \sqrt{n} = \sqrt{m+n} is incorrect

Choose positive integers m=1m=1 and n=1n=1.

Left side:

1+1=1+1=2\sqrt{1} + \sqrt{1} = 1 + 1 = 2

Right side:

1+1=2\sqrt{1+1} = \sqrt{2}

Since 2β‰ 22 \ne \sqrt{2}, the rule is false.

b) Show that mβˆ’n=mβˆ’n\sqrt{m} - \sqrt{n} = \sqrt{m-n} is incorrect

Choose positive integers m=9m=9 and n=4n=4.

Left side:

9βˆ’4=3βˆ’2=1\sqrt{9} - \sqrt{4} = 3 - 2 = 1

Right side:

9βˆ’4=5\sqrt{9-4} = \sqrt{5}

Since 1β‰ 51 \ne \sqrt{5}, the rule is false.

A compact way to remember it: square roots do not distribute over addition or subtraction.

πŸ’‘ Pitfall guide

The mistake is treating the radical sign like ordinary arithmetic parentheses. It does not β€œpass through” addition or subtraction. If you want to test a rule, use small perfect squares first; they make counterexamples very obvious.

πŸ”„ Real-world variant

If the numbers under the root are not perfect squares, the rule still fails. For example, 2+3β‰ 5\sqrt{2}+\sqrt{3}\neq\sqrt{5}. The only time expressions like this can simplify is when the radicals are like terms after simplification, not because the radicands were added or subtracted.

πŸ” Related terms

counterexample, radical rules, square root properties

FAQ

Can square roots be added by adding what is inside the root?

No. In general, √ m + √ n is not equal to √(m+n). A counterexample such as m=1 and n=1 proves the rule is false.

How do you show a math rule is incorrect?

Find one counterexample where the two sides give different values. If that happens, the rule is not always true.

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