Question

Finding an equivalent polar coordinate representation

Original question: The location of a point in the plane is given by polar coordinates (3,2π3)(-3,\frac{2\pi}{3}). Which of the following gives another representation for this point in polar coordinates?

A (3,5π3)(3,\frac{5\pi}{3}) B (3,2π3)(3,\frac{2\pi}{3}) C (3,π3)(3,\frac{\pi}{3}) D (3,7π3)(-3,\frac{7\pi}{3})

Correct A Correct. In this case, another representation is given by (3,2π3+π)(3,\frac{2\pi}{3}+\pi). Add or subtract a multiple of 2π2\pi to θ\theta to get another representation of the point, (r,θ+2nπ)(r,\theta+2n\pi). This does not change the location of the terminal ray for an angle in standard position, measuring counterclockwise from the polar (horizontal) axis. Consider r-r to be the same distance from the origin as rr but in the opposite direction of the terminal ray of the angle. Therefore, another representation of the point is given by (r,θ±(2n+1)π)(-r,\theta\pm (2n+1)\pi), where an odd multiple of π\pi is added or subtracted to θ\theta.

Expert Verified Solution

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Key concept: This question checks the two standard rules for polar coordinates: adding multiples of 2π2\pi and switching the sign of rr.

Step by step

Key idea

A polar point can be represented in more than one way. The two main equivalence rules are:

  1. (r,θ)(r,θ+2kπ)(r,\theta)\equiv(r,\theta+2k\pi)
  2. (r,θ)(r,θ+(2k+1)π)(r,\theta)\equiv(-r,\theta+(2k+1)\pi)

Here the given point is

(3,2π3).(-3,\tfrac{2\pi}{3}).

Because the radius is negative, we can rewrite the point with a positive radius by adding π\pi to the angle:

(3,2π3)(3,2π3+π).(-3,\tfrac{2\pi}{3})\equiv(3,\tfrac{2\pi}{3}+\pi).

Now simplify the angle:

2π3+π=2π3+3π3=5π3.\tfrac{2\pi}{3}+\pi=\tfrac{2\pi}{3}+\tfrac{3\pi}{3}=\tfrac{5\pi}{3}.

So the equivalent polar coordinate is

(3,5π3)\boxed{(3,\tfrac{5\pi}{3})}

which is choice A.

Why this works

A negative radius means you move in the direction opposite the terminal ray of the angle. Flipping the sign of rr requires a half-turn, which is exactly π\pi radians. That is why the angle changes by π\pi when rr changes sign.

If you only add 2π2\pi to the angle while keeping r=3r=-3, the location is still the same point, but the answer choices ask for another representation, and the positive-radius form is the clearest match.

Check the choices

  • A (3,5π3)(3,\frac{5\pi}{3}): correct, because it uses the same point with positive radius.
  • B (3,2π3)(3,\frac{2\pi}{3}): incorrect, because changing the sign of rr without changing the angle changes the point.
  • C (3,π3)(3,\frac{\pi}{3}): incorrect, because this is a different terminal ray.
  • D (3,7π3)(-3,\frac{7\pi}{3}): equivalent to the original point, but the intended standard equivalent form is still choice A.

So the correct answer is A\boxed{A}.

Pitfall alert

A frequent mistake is to think that changing rr from negative to positive does not affect the angle. In polar coordinates, a negative radius always points in the opposite direction, so the angle must shift by π\pi. Another error is adding 2π2\pi and expecting that alone to change a negative-radius point into a positive-radius point. It does not. The sign change and the angle shift work together. Also watch the trigonometric quadrant: 5π3\frac{5\pi}{3} is in Quadrant IV, which matches the direction opposite 2π3\frac{2\pi}{3}.

Try different conditions

If the point were (3,2π3)(3,\frac{2\pi}{3}), then an equivalent representation would be (3,5π3)(-3,\frac{5\pi}{3}), because switching the sign of rr requires adding π\pi to the angle. If the point were (3,7π3)(-3,\frac{7\pi}{3}), you could subtract 2π2\pi to rewrite it as (3,π3)(-3,\frac{\pi}{3}), which is still the same location. These variants show that either the radius sign changes with a π\pi shift, or the angle changes by multiples of 2π2\pi.

Further reading

polar coordinate equivalence, negative radius, terminal ray

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