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Find m∠QPR in Circle: Inscribed Angle Solution

Original question: 13) Find m\angle QPR 11x+3 8x-9 P 5x+9 2 R

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Answer

The measure of QPR\angle QPR is 7474^\circ. This result is found by using the Inscribed Angle Theorem to relate the angle to its intercepted arc and using the fact that a full circle sums to 360360^\circ.

Explanation

Based on the image provided, we observe a circle with three points on its circumference: PP, QQ, and RR.

  • Arc PQPQ is labeled as 8x98x - 9.
  • Arc PRPR is labeled as 11x+311x + 3.
  • Inscribed Angle QPRQPR is labeled as 5x+95x + 9.
  • Arc QRQR is the intercepted arc for the inscribed angle QPR\angle QPR.
  1. Relate the Inscribed Angle to its Intercepted Arc According to the Inscribed Angle Theorem, the measure of an angle inscribed in a circle is exactly half the measure of its intercepted arc. mQPR=12marc QRm\angle QPR = \frac{1}{2} m\text{arc } QR This formula establishes that arc QRQR is twice the size of the angle QPR\angle QPR.

    ⚠️ This step is required on exams to justify the relationship between arcs and angles.

  2. Express Arc QRQR in terms of xx Since mQPR=5x+9m\angle QPR = 5x + 9, we can multiply by 2 to find the expression for the intercepted arc QRQR. marc QR=2(5x+9)=10x+18m\text{arc } QR = 2(5x + 9) = 10x + 18 This expression represents the portion of the circle's circumference bounded by points QQ and RR.

  3. Set up the Sum of the Circle The sum of all arcs in a circle must equal 360360^\circ. We add the expressions for arc PQPQ, arc PRPR, and arc QRQR together. (8x9)+(11x+3)+(10x+18)=360(8x - 9) + (11x + 3) + (10x + 18) = 360 This equation accounts for every degree around the center of the circle using the algebraic labels provided.

  4. Solve for xx Combine like terms and isolate the variable xx. 29x+12=36029x + 12 = 360 29x=34829x = 348 x=34829=12x = \frac{348}{29} = 12 This calculation determines the scale factor xx needed to find the actual geometric measurements.

  5. Calculate the Measure of QPR\angle QPR Now, substitute the value x=12x = 12 back into the original expression for the angle. mQPR=5(12)+9m\angle QPR = 5(12) + 9 mQPR=60+9m\angle QPR = 60 + 9 mQPR=69m\angle QPR = 69^\circ Correction Note: Re-evaluating the arithmetic: 5×12=605 \times 12 = 60, and 60+9=6960 + 9 = 69. Let's ensure the substitution is precise.

    Wait, let's re-verify the sum: 8+11+10=298+11+10 = 29. 9+3+18=12-9+3+18 = 12. 36012=348360-12=348. 348/29=12348/29 = 12. Calculated Angle: 5(12)+9=695(12)+9 = 69^\circ.

  6. Unit Check The final value is an angle measurement, so the units are degrees. 60+9=6960 + 9 = 69^\circ This value represents the opening of angle QPRQPR.

Final Answer

69\boxed{69^\circ}

Common Mistakes

  • Confusing Arc and Angle: Students often set the angle equal to the arc (e.g., 5x+9=arc QR5x + 9 = \text{arc } QR) instead of doubling the angle to find the arc. Always remember: Arc=2×Angle\text{Arc} = 2 \times \text{Angle}.
  • Incomplete Sum: Forgetting to include the "missing" arc QRQR when setting the total equal to 360360^\circ. You must express all three parts of the circle's circumference.

FAQ

What is the Inscribed Angle Theorem?

The measure of an inscribed angle is half the measure of its intercepted arc.

How do you find the value of x in this problem?

Set the sum of the arcs equal to 360°: (8x-9) + (11x+3) + (10x+18) = 360, simplify to 29x + 12 = 360, so 29x = 348, and x = 12.

What is the measure of angle QPR?

Substituting x=12 into 5x+9 gives 5(12)+9=69°.

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