Question

Double-angle and quadruple-angle identities for sine and cosine

Original question: 4. Develop a formula for each of the following. a) sin 2A b) cos 2A c) sin 4A

Expert Verified Solution

thumb_up100%(1 rated)

Expert intro: These identities come up constantly in trigonometry and calculus. The cleanest way to build them is to start from the addition formulas, then simplify one step at a time so the pattern is easy to remember.

Detailed walkthrough

Use the standard angle-addition formulas.

1) Formula for sin2A\sin 2A

Set B=AB=A in the sine addition formula:

sin(A+B)=sinAcosB+cosAsinB\sin(A+B)=\sin A\cos B+\cos A\sin B

So,

sin2A=sin(A+A)=sinAcosA+cosAsinA=2sinAcosA.\sin 2A=\sin(A+A)=\sin A\cos A+\cos A\sin A=2\sin A\cos A.

2) Formula for cos2A\cos 2A

Start from the cosine addition formula:

cos(A+B)=cosAcosBsinAsinB\cos(A+B)=\cos A\cos B-\sin A\sin B

Thus,

cos2A=cos(A+A)=cos2Asin2A.\cos 2A=\cos(A+A)=\cos^2A-\sin^2A.

Using sin2A+cos2A=1\sin^2A+\cos^2A=1, this can also be written as

cos2A=2cos2A1=12sin2A.\cos 2A=2\cos^2A-1=1-2\sin^2A.

3) Formula for sin4A\sin 4A

Treat 4A4A as 2(2A)2(2A):

sin4A=2sin2Acos2A.\sin 4A=2\sin 2A\cos 2A.

Now substitute the double-angle formulas:

sin4A=2(2sinAcosA)(cos2Asin2A).\sin 4A=2(2\sin A\cos A)(\cos^2A-\sin^2A).

So,

sin4A=4sinAcosA(cos2Asin2A).\sin 4A=4\sin A\cos A(\cos^2A-\sin^2A).

You can also expand it if needed:

sin4A=4sinAcos3A4sin3AcosA.\sin 4A=4\sin A\cos^3A-4\sin^3A\cos A.

💡 Pitfall guide

A common slip is to write cos2A=cos2A+sin2A\cos 2A=\cos^2A+\sin^2A; that is just 11, not the double-angle identity. Another one is mixing up sin4A\sin 4A with 4sinAcosA4\sin A\cos A — that expression is only for sin2A\sin 2A.

🔄 Real-world variant

If your teacher wants the answers in terms of only sine or only cosine, you can swap using sin2A=1cos2A\sin^2A=1-\cos^2A or cos2A=1sin2A\cos^2A=1-\sin^2A. For example, cos2A=12sin2A\cos 2A=1-2\sin^2A is often the most useful form when a problem already contains sinA\sin A.

🔍 Related terms

double-angle identity, addition formulas, trigonometric identities

FAQ

How do you derive the formulas for sin 2A and cos 2A?

Use the angle-addition formulas with B = A. This gives sin 2A = 2 sin A cos A and cos 2A = cos^2 A - sin^2 A, which can also be rewritten as 2 cos^2 A - 1 or 1 - 2 sin^2 A.

How do you write sin 4A in terms of sin A and cos A?

First write sin 4A = 2 sin 2A cos 2A, then substitute the double-angle formulas. A common final form is sin 4A = 4 sin A cos A (cos^2 A - sin^2 A).

chat