Question

Exact value practice with sine, cosine, secant, cotangent, and cosecant

Original question: 1. Evaluate each of the following (exact values only) a) $\sin \frac{\pi}{3} - \cos \frac{\pi}{6}$ b) $\sec \frac{\pi}{6} + 2\cot \frac{\pi}{4}$ c) $\sin^2 \frac{\pi}{6} + \cos^2 \frac{\pi}{4}$ d) $4\sin \frac{\pi}{4} + \sec^2 \pi$ e) $\sqrt[3]{\csc \frac{\pi}{6}} - \sin^2 \frac{\pi}{2}$

Expert Verified Solution

thumb_up100%(1 rated)

Key takeaway: These expressions are built from standard unit-circle values. Once you know the special angles, each part falls out cleanly.

Evaluate each expression exactly.

a) sinπ3cosπ6\sin \frac{\pi}{3} - \cos \frac{\pi}{6}

sinπ3=32,cosπ6=32\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2},\qquad \cos \frac{\pi}{6}=\frac{\sqrt{3}}{2}

So

sinπ3cosπ6=0.\sin \frac{\pi}{3} - \cos \frac{\pi}{6}=0.

b) secπ6+2cotπ4\sec \frac{\pi}{6} + 2\cot \frac{\pi}{4}

secπ6=1cosπ6=13/2=23=233,\sec \frac{\pi}{6}=\frac{1}{\cos \frac{\pi}{6}}=\frac{1}{\sqrt{3}/2}=\frac{2}{\sqrt{3}}=\frac{2\sqrt{3}}{3},

and

cotπ4=1.\cot \frac{\pi}{4}=1.

Thus

secπ6+2cotπ4=233+2.\sec \frac{\pi}{6} + 2\cot \frac{\pi}{4}=\frac{2\sqrt{3}}{3}+2.

c) sin2π6+cos2π4\sin^2 \frac{\pi}{6} + \cos^2 \frac{\pi}{4}

sinπ6=12sin2π6=14,\sin \frac{\pi}{6}=\frac12 \Rightarrow \sin^2 \frac{\pi}{6}=\frac14,

cosπ4=22cos2π4=12.\cos \frac{\pi}{4}=\frac{\sqrt2}{2} \Rightarrow \cos^2 \frac{\pi}{4}=\frac12.

So

14+12=34.\frac14+\frac12=\frac34.

d) 4sinπ4+sec2π4\sin \frac{\pi}{4} + \sec^2 \pi

4sinπ4=422=22,4\sin \frac{\pi}{4}=4\cdot \frac{\sqrt2}{2}=2\sqrt2,

and

secπ=1cosπ=11=1sec2π=1.\sec \pi=\frac{1}{\cos \pi}=\frac{1}{-1}=-1 \Rightarrow \sec^2\pi=1.

Therefore

4sinπ4+sec2π=22+1.4\sin \frac{\pi}{4} + \sec^2 \pi=2\sqrt2+1.

e) cscπ63sin2π2\sqrt[3]{\csc \frac{\pi}{6}} - \sin^2 \frac{\pi}{2}

cscπ6=1sinπ6=2,\csc \frac{\pi}{6}=\frac{1}{\sin \frac{\pi}{6}}=2,

so

cscπ63=23.\sqrt[3]{\csc \frac{\pi}{6}}=\sqrt[3]{2}.

Also,

sinπ2=1sin2π2=1.\sin \frac{\pi}{2}=1 \Rightarrow \sin^2 \frac{\pi}{2}=1.

Thus

cscπ63sin2π2=231.\sqrt[3]{\csc \frac{\pi}{6}} - \sin^2 \frac{\pi}{2}=\sqrt[3]{2}-1.

Final answers

  • a) 00
  • b) 233+2\frac{2\sqrt3}{3}+2
  • c) 34\frac34
  • d) 22+12\sqrt2+1
  • e) 231\sqrt[3]{2}-1

Pitfalls the pros know 👇 Two places people slip are reciprocal functions and exponents. Remember that secx=1/cosx\sec x=1/\cos x and cscx=1/sinx\csc x=1/\sin x, then square only after the reciprocal is taken. Also, sec2π\sec^2\pi means (secπ)2(\sec \pi)^2, not sec(2π)\sec(2\pi).

What if the problem changes? If the angles were replaced with nearby special angles, the method would be the same: evaluate the base trig value first, then apply any reciprocal, power, or root. If an angle is not a standard one, you would usually need a calculator approximation instead of an exact radical form.

Tags: unit circle values, reciprocal identities, special angles

FAQ

How do I evaluate exact trig expressions with sec, cot, and csc?

Rewrite reciprocal functions using sine and cosine, then substitute known unit-circle values for special angles such as pi/6, pi/4, pi/3, and pi/2.

Why does sec^2(pi) equal 1?

Because sec(pi) = 1/cos(pi) = -1, and squaring gives (-1)^2 = 1.

chat