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Carrying Out a Chi-Square Test for Homogeneity or Independence

AP Statistics· difficulty 2/5

Software reports: chi-square = 8.40, df = 4, p = 0.078.

Output chi-square = 8.40 df = 4 p-value = 0.078

At alpha = 0.05, conclusion?

  • A

    Fail to reject H0; insufficient evidence of association

    check_circle
  • B

    Reject H0

  • C

    p too low to interpret

  • D

    Accept H0

Explanation

Since p = 0.078 > alpha = 0.05, fail to reject H0. There is insufficient evidence of association.

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