Carrying Out a Chi-Square Test for Homogeneity or Independence

AP Statistics· difficulty 2/5

A chi-square test of independence with df = 6 produces chi-square = 14.5 and p-value = 0.024. Use alpha = 0.05.

df=6, chi-sq=14.5, p=0.024 14.5

What is the correct conclusion?

  • A

    Reject H0; there is significant evidence of an association

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  • B

    Accept H0; the variables are independent

  • C

    Reject H0; the variables are independent

  • D

    Fail to reject H0; no evidence of association

Explanation

Since p-value (0.024) < alpha (0.05), reject H0. There is significant evidence of an association between the two variables.

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