Confidence Intervals for the Difference of Two Proportions

AP Statistics· difficulty 3/5

p̂₁ = 0.6 (n₁=100), p̂₂ = 0.4 (n₂=100).

SE_CI = sqrt(0.6·0.4/100 + 0.4·0.6/100) = sqrt(0.0048)

SE for the CI is approximately:

  • A

    0.0245

  • B

    0.1000

  • C

    0.0490

  • D

    0.0693

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Explanation

SE = sqrt(0.0024 + 0.0024) = sqrt(0.0048) ≈ 0.0693.

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