Constructing a two-sample z-interval for p₁ − p₂.
Why do we use unpooled SE for the CI but pooled SE for the test?
- Acheck_circle
The test assumes p₁ = p₂ under H₀, so we pool; the CI does not assume equality.
- B
Pooled SE is always larger and more accurate.
- C
It's an arbitrary convention without theoretical basis.
- D
The CI requires more conservative estimates, so unpooled.
Explanation
Under H₀ (p₁ = p₂), pooling gives a better estimate of the common proportion. CIs do not assume the proportions are equal.