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Constructing a Confidence Interval for a Population Proportion

AP Statistics· difficulty 3/5

Researcher wants ME = 0.02 at 95% confidence with no prior information.

n ≥ (1.96)²(0.5)(0.5)/(0.02)² n ≥ 0.9604/0.0004

What is the minimum n?

  • A

    9604

  • B

    2401

    check_circle
  • C

    385

  • D

    1068

Explanation

n ≥ (1.96)²·(0.25)/(0.02)² = 0.9604/0.0004 = 2401.

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