369 n ≥ (1.96/0.05)²·(0.24) = 1536.64·0.24 = 368.79, round up to 369.

Constructing a Confidence Interval for a Population Proportion

AP Statistics· difficulty 3/5

Estimate p̂ \approx 0.40 from a pilot study. Want 95% CI with ME \leq 0.05.

Minimum n required:

Explanation

n \geq (1.96/0.05)²\cdot(0.24) = 1536.64\cdot0.24 = 368.79, round up to 369.

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