For 3 mutually exclusive events with probabilities 0.2, 0.3, 0.4, P(none) =
- A
0.2
- B
0.5
- Ccheck_circle
0.1
- D
0.9
Explanation
P(any) = 0.9; P(none) = 1 − 0.9 = 0.1.
AP Statistics· difficulty 3/5
For 3 mutually exclusive events with probabilities 0.2, 0.3, 0.4, P(none) =
0.2
0.5
0.1
0.9
Explanation
P(any) = 0.9; P(none) = 1 − 0.9 = 0.1.
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