For mutually exclusive A, B: P(A or B) =
- A
1 − P(A)P(B)
- B
P(A) · P(B)
- C
P(A) + P(B) − P(A∩B)
- Dcheck_circle
P(A) + P(B)
Explanation
Mutually exclusive ⇒ P(A∩B) = 0.
AP Statistics· difficulty 2/5
For mutually exclusive A, B: P(A or B) =
1 − P(A)P(B)
P(A) · P(B)
P(A) + P(B) − P(A∩B)
P(A) + P(B)
Explanation
Mutually exclusive ⇒ P(A∩B) = 0.
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