Setting Up a Chi-Square Goodness of Fit Test

AP Statistics· difficulty 4/5

A die rolled 60 times yields counts 8, 12, 9, 11, 10, 10. Under H0H_0 that the die is fair, the expected count per face is 10. The chi-square statistic is approximately

  • A

    6060

  • B

    1.01.0

    check_circle
  • C

    5.995.99

  • D

    0.010.01

Explanation

χ² = Σ(O-E)²/E = (4+4+1+1+0+0)/10 = 10/10 = 1.0. With df=5, this is far below the critical value (~11.07 at α=0.05) → fail to reject.

Want 10 more like this — adaptive to your weak spots?

Related questions