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Tests for the Difference of Two Proportions

AP Statistics· difficulty 4/5

To test H0:p1=p2H_0: p_1 = p_2 against Ha:p1≠p2H_a: p_1 \neq p_2 with samples of n1=200n_1 = 200, n2=200n_2 = 200 giving 60 and 80 successes, the pooled proportion is

  • A

    0.350.35

    check_circle
  • B

    0.400.40

  • C

    0.500.50

  • D

    0.300.30

Explanation

p̂_pool = (60+80)/(200+200) = 140/400 = 0.35.

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