Expected Counts in Two-Way Tables

AP Statistics· difficulty 4/5

Expected count for a cell in a chi-square test of independence is

A
$Cell count itself$
B
$(row total \times column total)/n$
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C
$row total + column total$
D
$n \times proportion$

Explanation

Under independence, E_ij = (r_i \times c_j)/n.

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