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Right Triangles and Trigonometry

SAT Math· difficulty 3/5

Simplify sin⁡2θ1−cos⁡2θ\frac{\sin^2\theta}{1-\cos^2\theta} for acute θ\theta.

  • A

    11

    check_circle
  • B

    cos⁡θ\cos\theta

  • C

    00

  • D

    sin⁡θ\sin\theta

Explanation

1−cos⁡2θ=sin⁡2θ1-\cos^2\theta=\sin^2\theta, so the expression equals sin⁡2θsin⁡2θ=1\frac{\sin^2\theta}{\sin^2\theta}=1.

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