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Circles

SAT Math· difficulty 2/5

What is the center of the circle with equation (x−3)2+(y+5)2=16(x-3)^2 + (y+5)^2 = 16?

  • A

    (3,−5)(3, -5)

    check_circle
  • B

    (−3,5)(-3, 5)

  • C

    (−3,−5)(-3, -5)

  • D

    (3,5)(3, 5)

Explanation

The standard form is (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2 where (h,k)(h,k) is the center. Here h=3h=3, k=−5k=-5, so the center is (3,−5)(3, -5).

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