SAT Math · Topic 4.4

Circles Practice

Part of Geometry and Trigonometry.

Practice questions

56

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Sample questions

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  1. Sample 1difficulty 2/5

    What is the radius of the circle with equation (x2)2+(y7)2=49(x-2)^2 + (y-7)^2 = 49?

    • A

      7

      check_circle
    • B

      14

    • C

      49

    • D

      7\sqrt{7}

    Why

    In standard form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2, we have r2=49r^2 = 49, so r=7r = 7.

  2. Sample 2difficulty 2/5

    A circle has diameter 10. What is its circumference?

    • A

      20π20\pi

    • B

      5π5\pi

    • C

      25π25\pi

    • D

      10π10\pi

      check_circle

    Why

    Circumference =pid=pi(10)=10pi= \\pi d = \\pi(10) = 10\\pi.

  3. Sample 3difficulty 2/5

    A circle has radius 7. What is its circumference?

    • A

      28π28\pi

    • B

      14π14\pi

      check_circle
    • C

      49π49\pi

    • D

      7π7\pi

    Why

    Circumference =2pir=2pi(7)=14pi= 2\\pi r = 2\\pi(7) = 14\\pi.

  4. Sample 4difficulty 2/5

    What is the center of the circle with equation (x3)2+(y+5)2=16(x-3)^2 + (y+5)^2 = 16?

    • A

      (3,5)(3, -5)

      check_circle
    • B

      (3,5)(-3, 5)

    • C

      (3,5)(-3, -5)

    • D

      (3,5)(3, 5)

    Why

    The standard form is (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2 where (h,k)(h,k) is the center. Here h=3h=3, k=5k=-5, so the center is (3,5)(3, -5).

  5. Sample 5difficulty 2/5

    A circle has radius 6. What is its area?

    • A

      36π36\pi

      check_circle
    • B

      72π72\pi

    • C

      12π12\pi

    • D

      6π6\pi

    Why

    Area =pir2=pi(6)2=36pi= \\pi r^2 = \\pi(6)^2 = 36\\pi.