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Linear Equations in One Variable

SAT Math· difficulty 4/5

For what value of aa is the line ax+4y=12ax + 4y = 12 parallel to the line 3x−2y=53x - 2y = 5?

  • A

    3

  • B

    6

  • C

    −6-6

    check_circle
  • D

    −3-3

Explanation

Slope of 3x−2y=53x - 2y = 5 is 32\frac{3}{2}. For ax+4y=12ax + 4y = 12, slope is −a4-\frac{a}{4}. Set −a4=32-\frac{a}{4} = \frac{3}{2}: a=−6a = -6.

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