SAT Math · Topic 1.1

Linear Equations in One Variable Practice

Part of Algebra.

Practice questions

190

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Sample questions

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  1. Sample 1difficulty 2/5

    If x4+2=7\frac{x}{4} + 2 = 7, what is the value of xx?

    • A

      94\frac{9}{4}

    • B

      9

    • C

      20

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    • D

      5

    Why

    Subtract 2: x4=5\frac{x}{4} = 5. Multiply by 4: x=20x = 20.

  2. Sample 2difficulty 2/5

    What are the solutions to x4=7|x - 4| = 7?

    • A

      x=11x = 11 only

    • B

      x=3x = -3 or x=11x = 11

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    • C

      x=3x = 3 or x=11x = -11

    • D

      x=3x = -3 only

    Why

    x4=7x - 4 = 7 gives x=11x = 11; x4=7x - 4 = -7 gives x=3x = -3.

  3. Sample 3difficulty 2/5

    A bag contains nickels and dimes worth \2.50$ total. There are 30 coins in all. How many dimes are in the bag?

    • A

      20

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    • B

      25

    • C

      10

    • D

      15

    Why

    Let nn = nickels, dd = dimes. n+d=30n + d = 30, 0.05n+0.10d=2.500.05n + 0.10d = 2.50. Substitute n=30dn = 30 - d: 0.05(30d)+0.10d=2.500.05(30-d) + 0.10d = 2.501.5+0.05d=2.501.5 + 0.05d = 2.50d=20d = 20.

  4. Sample 4difficulty 2/5

    If x4=3|x - 4| = 3, which of the following could be a value of xx?

    • A

      1-1

    • B

      12

    • C

      7-7

    • D

      1

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    Why

    x4=3x - 4 = 3 gives x=7x = 7, or x4=3x - 4 = -3 gives x=1x = 1. Among the choices, 1 works.

  5. Sample 5difficulty 2/5

    If 3x7=143x - 7 = 14, what is the value of xx?

    • A

      5

    • B

      7

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    • C

      73\frac{7}{3}

    • D

      21

    Why

    Add 7 to both sides: 3x=213x = 21. Divide by 3: x=7x = 7.