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Linear Equations in One Variable

SAT Math· difficulty 4/5

For what value of cc does the equation 12(6x−4)=3x+c\frac{1}{2}(6x - 4) = 3x + c have no solution?

  • A

    Any c≠2c \ne 2

  • B

    Any c≠−2c \ne -2

    check_circle
  • C

    c=2c = 2

  • D

    c=−2c = -2

Explanation

3x−2=3x+c3x - 2 = 3x + c simplifies to −2=c-2 = c. If c=−2c = -2, infinite solutions. If c≠−2c \ne -2, no solution.

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