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Nonlinear Functions

SAT Math· difficulty 5/5

Which function has both vertical asymptote at x=2x = 2 and horizontal asymptote at y=−1y = -1?

  • A

    y=−x+3x−2y = \frac{-x + 3}{x - 2}

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  • B

    y=−x−1x+2y = \frac{-x - 1}{x + 2}

  • C

    y=x+1x−2y = \frac{x + 1}{x - 2}

  • D

    y=x−12−xy = \frac{x - 1}{2 - x}

Explanation

Vertical: x−2=0⇒x=2x - 2 = 0 \Rightarrow x = 2. Horizontal: leading coefficients ratio −11=−1\frac{-1}{1} = -1.

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