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Nonlinear Functions

SAT Math· difficulty 4/5

A 100 g sample with half-life 6 years remains at what amount (in grams) after 9 years?

  • A

    10022\dfrac{100}{2\sqrt{2}}

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  • B

    1004\dfrac{100}{4}

  • C

    1002\dfrac{100}{2}

  • D

    1003\dfrac{100}{3}

Explanation

Amount =100⋅(1/2)9/6=100⋅(1/2)3/2=100/(22)= 100 \cdot (1/2)^{9/6} = 100 \cdot (1/2)^{3/2} = 100/(2\sqrt{2}).

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