If f(x)=1x−2f(x) = \frac{1}{x - 2}f(x)=x−21 and g(x)=x+2g(x) = x + 2g(x)=x+2, what is f(g(x))f(g(x))f(g(x))?Ax+2x + 2x+2B1x+2\frac{1}{x + 2}x+21C1x\frac{1}{x}x1check_circleD1x−4\frac{1}{x - 4}x−41Explanationf(g(x))=1g(x)−2=1(x+2)−2=1xf(g(x)) = \frac{1}{g(x) - 2} = \frac{1}{(x + 2) - 2} = \frac{1}{x}f(g(x))=g(x)−21=(x+2)−21=x1.