What is the inverse of f(x)=x+52f(x) = \frac{x + 5}{2}f(x)=2x+5?Af−1(x)=2x+5f^{-1}(x) = 2x + 5f−1(x)=2x+5Bf−1(x)=2x+5f^{-1}(x) = \frac{2}{x + 5}f−1(x)=x+52Cf−1(x)=2x−5f^{-1}(x) = 2x - 5f−1(x)=2x−5check_circleDf−1(x)=x−52f^{-1}(x) = \frac{x - 5}{2}f−1(x)=2x−5Explanationy=x+52⇒2y=x+5⇒x=2y−5y = \frac{x + 5}{2} \Rightarrow 2y = x + 5 \Rightarrow x = 2y - 5y=2x+5⇒2y=x+5⇒x=2y−5, so f−1(x)=2x−5f^{-1}(x) = 2x - 5f−1(x)=2x−5.