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Nonlinear Functions

SAT Math· difficulty 4/5

What is the horizontal asymptote of y=2x2+14x2−3y = \frac{2x^2 + 1}{4x^2 - 3}?

  • A

    y=12y = \frac{1}{2}

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  • B

    y=0y = 0

  • C

    y=−3y = -3

  • D

    y=2y = 2

Explanation

Equal degrees, so the horizontal asymptote is the ratio of leading coefficients: 24=12\frac{2}{4} = \frac{1}{2}.

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