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Nonlinear Functions

SAT Math· difficulty 4/5

A parabola has axis of symmetry x=3x = 3 and passes through (1,8)(1, 8) and (5,8)(5, 8). If its minimum value is 0, what is its equation?

  • A

    y=2(x+3)2y = 2(x+3)^2

  • B

    y=(x−3)2y = (x-3)^2

  • C

    y=(x+3)2y = (x+3)^2

  • D

    y=2(x−3)2y = 2(x-3)^2

    check_circle

Explanation

Vertex (3,0)(3, 0): y=a(x−3)2y = a(x-3)^2. At (1,8)(1, 8): 8=4a8 = 4a, a=2a = 2. So y=2(x−3)2y = 2(x-3)^2.

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