Which is a factor of p(x)=x3−7x+6p(x) = x^3 - 7x + 6p(x)=x3−7x+6?Ax−1x - 1x−1check_circleBx+3x + 3x+3Cx−2x - 2x−2Dx−4x - 4x−4Explanationp(1)=1−7+6=0p(1) = 1 - 7 + 6 = 0p(1)=1−7+6=0, so x−1x - 1x−1 is a factor.