Solve x2−4x+1=0x^2 - 4x + 1 = 0x2−4x+1=0.Ax=−2±3x = -2 \pm \sqrt{3}x=−2±3Bx=2±3x = 2 \pm \sqrt{3}x=2±3check_circleCx=2±5x = 2 \pm \sqrt{5}x=2±5Dx=4±3x = 4 \pm \sqrt{3}x=4±3Explanationx=4±16−42=4±232=2±3x = \frac{4 \pm \sqrt{16-4}}{2} = \frac{4 \pm 2\sqrt{3}}{2} = 2 \pm \sqrt{3}x=24±16−4=24±23=2±3.