If x=3x = 3x=3 is a zero of p(x)=2x3+bx2−5x−12p(x) = 2x^3 + bx^2 - 5x - 12p(x)=2x3+bx2−5x−12, what is the value of bbb?A555B−5-5−5C333D−3-3−3check_circleExplanationp(3)=54+9b−15−12=27+9b=0⇒b=−3p(3) = 54 + 9b - 15 - 12 = 27 + 9b = 0 \Rightarrow b = -3p(3)=54+9b−15−12=27+9b=0⇒b=−3.