The equation kx2−(k+1)x+1=0kx^2 - (k+1)x + 1 = 0kx2−(k+1)x+1=0 has two equal roots (k≠0k \ne 0k=0). What is kkk?Ak=2k = 2k=2Bk=1k = 1k=1check_circleCk=−1k = -1k=−1Dk=1/2k = 1/2k=1/2ExplanationD=(k+1)2−4k=k2+2k+1−4k=(k−1)2=0D = (k+1)^2 - 4k = k^2 + 2k + 1 - 4k = (k-1)^2 = 0D=(k+1)2−4k=k2+2k+1−4k=(k−1)2=0, so k=1k = 1k=1.