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Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 4/5

Solve x2−8x+13=0x^2 - 8x + 13 = 0.

  • A

    x=8±3x = 8 \pm \sqrt{3}

  • B

    x=−4±3x = -4 \pm \sqrt{3}

  • C

    x=4±3x = 4 \pm \sqrt{3}

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  • D

    x=4±13x = 4 \pm \sqrt{13}

Explanation

x=8±64−522=8±232=4±3x = \frac{8 \pm \sqrt{64-52}}{2} = \frac{8 \pm 2\sqrt{3}}{2} = 4 \pm \sqrt{3}.

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