The roots of x3−6x2+11x−6=0x^3 - 6x^2 + 11x - 6 = 0x3−6x2+11x−6=0 are:Ax=−1,−2,−3x = -1, -2, -3x=−1,−2,−3Bx=1,6,−1x = 1, 6, -1x=1,6,−1Cx=1,2,3x = 1, 2, 3x=1,2,3check_circleDx=1,2,6x = 1, 2, 6x=1,2,6ExplanationTest x=1x = 1x=1: 1−6+11−6=01 - 6 + 11 - 6 = 01−6+11−6=0 ✓. Divide by x−1x - 1x−1: quotient x2−5x+6=(x−2)(x−3)x^2 - 5x + 6 = (x-2)(x-3)x2−5x+6=(x−2)(x−3). Roots: 1,2,31, 2, 31,2,3.