Solve 3x2−x−2=03x^2 - x - 2 = 03x2−x−2=0.Ax=−1,2/3x = -1, 2/3x=−1,2/3Bx=1,−2/3x = 1, -2/3x=1,−2/3check_circleCx=−1,−2/3x = -1, -2/3x=−1,−2/3Dx=1,2/3x = 1, 2/3x=1,2/3Explanation(3x+2)(x−1)=0(3x+2)(x-1) = 0(3x+2)(x−1)=0, so x=1x = 1x=1 or x=−2/3x = -2/3x=−2/3.