Solve (2x+1)2=25(2x+1)^2 = 25(2x+1)2=25.Ax=2,−3x = 2, -3x=2,−3check_circleBx=−3x = -3x=−3 onlyCx=12,−13x = 12, -13x=12,−13Dx=2x = 2x=2 onlyExplanation2x+1=±52x + 1 = \pm 52x+1=±5. So 2x=42x = 42x=4 or 2x=−62x = -62x=−6: x=2x = 2x=2 or x=−3x = -3x=−3.