If g(x)=f(x−3)+2g(x) = f(x-3) + 2g(x)=f(x−3)+2 and f(x)=x2f(x) = x^2f(x)=x2, what is g(x)g(x)g(x) in standard form?Ax2−6x+11x^2 - 6x + 11x2−6x+11check_circleBx2+6x+11x^2 + 6x + 11x2+6x+11Cx2−6x+9x^2 - 6x + 9x2−6x+9Dx2−6x+7x^2 - 6x + 7x2−6x+7Explanationg(x)=(x−3)2+2=x2−6x+9+2=x2−6x+11g(x) = (x-3)^2 + 2 = x^2 - 6x + 9 + 2 = x^2 - 6x + 11g(x)=(x−3)2+2=x2−6x+9+2=x2−6x+11.