For what values of mmm does x2+(m+1)x+(m+4)=0x^2 + (m+1)x + (m+4) = 0x2+(m+1)x+(m+4)=0 have no real solutions?Am<−5m < -5m<−5 or m>3m > 3m>3B−3<m<5-3 < m < 5−3<m<5check_circleC−5<m<3-5 < m < 3−5<m<3Dm<−3m < -3m<−3 or m>5m > 5m>5ExplanationD=(m+1)2−4(m+4)=m2+2m+1−4m−16=m2−2m−15<0D = (m+1)^2 - 4(m+4) = m^2 + 2m + 1 - 4m - 16 = m^2 - 2m - 15 < 0D=(m+1)2−4(m+4)=m2+2m+1−4m−16=m2−2m−15<0. (m−5)(m+3)<0(m-5)(m+3) < 0(m−5)(m+3)<0: −3<m<5-3 < m < 5−3<m<5.