Solve x2+2x−5=0x^2 + 2x - 5 = 0x2+2x−5=0.Ax=−2±6x = -2 \pm \sqrt{6}x=−2±6Bx=−1±6x = -1 \pm \sqrt{6}x=−1±6check_circleCx=−1±5x = -1 \pm \sqrt{5}x=−1±5Dx=1±6x = 1 \pm \sqrt{6}x=1±6Explanationx=−2±4+202=−2±262=−1±6x = \frac{-2 \pm \sqrt{4+20}}{2} = \frac{-2 \pm 2\sqrt{6}}{2} = -1 \pm \sqrt{6}x=2−2±4+20=2−2±26=−1±6.