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Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 4/5

A ball's height is h(t)=−16t2+48t+4h(t) = -16t^2 + 48t + 4 feet. At what time(s) is the ball at height 36 feet?

  • A

    t=0.5t = 0.5 and t=2.5t = 2.5

  • B

    t=2t = 2 only

  • C

    t=1t = 1 only

  • D

    t=1t = 1 and t=2t = 2

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Explanation

−16t2+48t+4=36-16t^2 + 48t + 4 = 36, −16t2+48t−32=0-16t^2 + 48t - 32 = 0, t2−3t+2=0t^2 - 3t + 2 = 0, t=1,2t = 1, 2.

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