Solve x2−9≥0x^2 - 9 \ge 0x2−9≥0.A−3≤x≤3-3 \le x \le 3−3≤x≤3Bx≤−3x \le -3x≤−3 or x≥3x \ge 3x≥3check_circleCx≥3x \ge 3x≥3Dx≤−3x \le -3x≤−3Explanation(x−3)(x+3)≥0(x-3)(x+3) \ge 0(x−3)(x+3)≥0 outside the roots: x≤−3x \le -3x≤−3 or x≥3x \ge 3x≥3.