Solve 2x2+5x+1=02x^2 + 5x + 1 = 02x2+5x+1=0.Ax=−5±334x = \frac{-5 \pm \sqrt{33}}{4}x=4−5±33Bx=−5±174x = \frac{-5 \pm \sqrt{17}}{4}x=4−5±17check_circleCx=−5±172x = \frac{-5 \pm \sqrt{17}}{2}x=2−5±17Dx=5±174x = \frac{5 \pm \sqrt{17}}{4}x=45±17Explanationx=−5±25−84=−5±174x = \frac{-5 \pm \sqrt{25-8}}{4} = \frac{-5 \pm \sqrt{17}}{4}x=4−5±25−8=4−5±17.