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Heat Capacity and Calorimetry

AP Chemistry· difficulty 4/5

50.0 g of water (c = 4.18 J/g·K) at 80.0°C is mixed with 100.0 g of water at 20.0°C in a perfect calorimeter. Final temperature is

  • A

    60.0°C

  • B

    40.0°C (weighted average: (50×80 + 100×20)/150)

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  • C

    30.0°C

  • D

    50.0°C

Explanation

Energy conservation: m1c(Tf−T1)+m2c(Tf−T2)=0m_1 c (T_f - T_1) + m_2 c (T_f - T_2) = 0. Tf=(50×80+100×20)/150=(4000+2000)/150=40T_f = (50×80 + 100×20)/150 = (4000 + 2000)/150 = 40°C.

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